Algebra 1, 2011
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 PAGE: 348 SET: Exercises PROBLEM: 1
Please look in your text book for this problem Statement

First find the minimum point of the graph.

Since absolute value function can not be negative, the minimum

point of the graph is where .

The original function is .

Set original function

(Add 8 to each side)

(Apply additive inverse property: )

(Apply additive identity property: )

Next make at table, fill out the table with values for x > 8 and  x < 8.

 f(x) = | x | – 8 x f(x) – 2 – 6 –1 – 7 0 – 8 1 – 7 2 – 6

First, draw a co-ordinate plane.

Locate the points on co-ordinate plane and draw the graph through these points.

Graph for the absolute value function

Observe the graphs, both graphs have same shape and

points on are 8 units lower than the points on .

The graph of  is the graph of and translated 8 units down.

The graph of  is the graph of and translated 8 units down.

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