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| PAGE: 350 | SET: Exercises | PROBLEM: 32 |
The equations are 
.
First find the minimum point of the graph.
Since absolute value function can not be negative,
the minimum point of the graph is where 
.
The original function is 
.
Set original function 
(Subtract 7 from each side)
(Apply additive inverse property: 
)
(Apply additive identity property: 
)
(Multiply each side by negative one)
(Product of two same signs is positive)
The original function is 
.
Set original function
(Add 3 to each side)
(Apply additive inverse property: 
)
(Apply additive identity property: 
)
Next make at table, fill out the table with values for x > 3 and x < 3, 
.
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5 |
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6 |
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0 |
3 |
0 |
7 |
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2 |
1 |
1 |
6 |
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4 |
1 |
2 |
5 |
First, draw a co-ordinate plane.
Locate the points on co-ordinate plane and draw the graph through these points.
=abs(x-3)_and_f(x)=-abs(x)+7.gif)
Observe the graphs, both graphs have different shapes and
points on and have common point is 
.
The graphs of and have in common point is .
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