  PRE-ALGEBRA
ALGEBRA 1
GEOMETRY
ALGEBRA 2
TRIGONOMETRY
PRE-CALCULUS
CALCULUS    Algebra 1, 2011 SELECT PAGE NO. SELECT PROBLEM NO. FOR THE PAGE

 PAGE: 297 SET: Exercises PROBLEM: 23
Please look in your text book for this problem Statement   The line equation in slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept.

Write the two functions as co-ordinates.   First find the slope  (Substitute ) (Product of two same signs is positive) (Subtract: ) (Add: 2 + 1 = 3) (Divide: ) Next find the y-intercept

Substitute the slope and the coordinates of the given point in slope-intercept form equation.

y = mx + b

15–2(–2) + b                   (Substitute 2 for m, – 2 for x, and 15 for y)

154 + b                            (Multiply: )

15 – 4 = 4 4 + b               (Subtract 4 from each side)

15 – 4 = b                            (Apply additive inverse property: 4 4= 0)

b = 11                                  (Subtract: 15 – 4 = 11) Finally write the line equation

Substitute the values of slope ‘m’ and y-intercept ‘b’ in slope intercept form line equation.

y = mx + b

y = –2(x) + 11                    (Substitute 2 for m and 11 for b)

y = –2x + 11                      (Simplify) The function is y = –2x + 11. TESTIMONIALS
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