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32

Step-by-step Answer
PAGE: 725SET: ExercisesPROBLEM: 32
Please look in your text book for this problem Statement

The equation is .

Solve the equation.

                                     (Original equation)

                            (LCM of is )

                                  (Apply distributive property: )

                                              (Combine like terms)

                                          (Factors)

    (Multiply each side by )

                                 (Cancel common terms)

                            (Divide each side by )

                                                          (Cancel common terms)

                                              (Subtract from each side)

                                                                  (Apply additive inverse property: )

Hence, there is no varible term,so can not define the factors.

Since, the results can not define the original equation.

There is no slolution.

It is an extraneous solution.

There is no solution and it is an extraneous solution.



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