The equation is .
Solve the equation.
(Original equation)
(LCM of is )
(Apply distributive property: )
(Combine like terms)
(Factors)
(Multiply each side by )
(Cancel common terms)
(Divide each side by )
(Cancel common terms)
(Subtract from each side)
(Apply additive inverse property: )
Hence, there is no varible term,so can not define the factors.
Since, the results can not define the original equation.
There is no slolution.
It is an extraneous solution.
There is no solution and it is an extraneous solution.
"I want to tell you that our students did well on the math exam and showed a marked improvement that, in my estimation, reflected the professional development the faculty received from you. THANK YOU!!!" June Barnett |
"Your site is amazing! It helped me get through Algebra." Charles |
"My daughter uses it to supplement her Algebra 1 school work. She finds it very helpful." Dan Pease |