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49

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PAGE: 216SET: ExercisesPROBLEM: 49
Please look in your text book for this problem Statement

One of the curve has three zeros at , and .

Since curve has three -intercepts it is a third degree polynomial.

The curve has zeros at and .

Since curve has two -intercepts it is a second degree polynomial.

The curve has zero at .

Since curve has one -intercept it is a first degree polynomial.

The third degree polynomial be the original function .

The derivative of a cubic function is a second degree function that means is a quadratic function.

The derivative of a second degree function is a first degree function means is a linear function.

Therefore third degree polynomial is correspond to

Simillarly second degree is correspond to .

First degree is correspond to .

Graph :

Draw a coordinate plane Indicate the functions , and correspondingly.

.

Draw a coordinate plane Indicate the functions , and correspondingly.

.



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