Precalculus 2014
31

 PAGE: 265 SET: Exercises PROBLEM: 31

The equation correspond to the graph is .

Observe the graph :

The distance from the maximum to the minimum value of the function is

Half of the distance from the maximum to the minimum value of the function is

So the amplitude is .

Period

Here the function completes one period on .

Substitute Period in Period .

The midline appears at , there is no vertical shift.

Since the midline appears at , the value of is zero.

Since  there is no vertical shift, the value of is zero.

Substitute , , and  .

The equation correspond to the graph is .

The equation correspond to the graph is .

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