The equation is .
According to division property of equality: if , then
.
(Divide each side by negative 3)
(Cancel common terms)
(Divide:
)
Write two cases:
\Case-1: a = b
\Case-2: a = b
Solve the equation for Case-1.
\According to subtraction property of equality: if , then
.
(Subtract 5 from each side)
\
( Apply Additive inverse property:
)
(Subtract:
)
(Divide each side by 2)
(Cancel common terms)
Check:
\To check the solution, substitute in original equation.
(Product of two different signs is positive)
(Add:
)
(Absolute value: |3| = 3)
(Multiply:
)
Compare the values the equation is true. is a solution.
Solve the equation for Case-2.
\According to subtraction property of equality: if , then
.
(Subtract 5 from each side)
\
(Apply Additive inverse property:
)
(Subtract:
)
(Divide each side by 2)
(Cancel common terms)
(Divide:
)
Check:
\To check the solution, substitute in original equation.
(Multiply:
)
(Subtract :
)
(Absolute value: |
3| = 3)
(Multiply:
)
Compare the values the equation is true. is a solution.
The solutions are -1 and . The solution set is
.