$\"\"$

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The line passes through the points are $\"\"$ and perpendicular to $\"\"$ .

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Rewrite the equation.

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$\"\"$ (Original equation) \ \

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$\"\"$ (Add $\"\"$ to each side)

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$\"\"$ (Apply additive inverse property: $\"\"$ )

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$\"\"$ (Divide each side by $\"\"$ )

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$\"\"$ (Cancel common terms)

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Hence the slope of the line equation is $\"\"$ ,then perpendicular line slope is $\"\"$ .

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Point slope-intercept form of the equation of a line is $\"\"$ .

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Find the point slope intercept line equation.

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$\"\"$ (Formula for Point-slopeintercept)

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$\"\"$ (Substitute $\"\"$ and $\"\"$ )

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$\"\"$ (Distributive property: $\"\"$ )

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$\"\"$ (Simplify)

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Therefore, the point slope intercept form of the line eqaution is $\"\"$ .

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$\"\"$

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Check the solution by using graphing method.

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Graph of the equations are $\"\"$ and $\"\"$ .

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$\"\"$

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Observe the graph:

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The both equations are perpendicular lines.

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$\"\"$

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The point slope intercept form of the line eqaution is $\"\"$ .