\"\"

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Three times the difference of four times a number and three times  a second number is \"\".

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Let \"\" be a first number and \"\" be a second number.

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Hence the equation is \"\".

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Four times the sum of \"\" times the second number and \"\" times the first number is \"\".

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Hence the equation is \"\".

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The system of equations are \"\" and \"\".

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\"\"

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Solve the system of equations by elimination method.

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Step 1:

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Multiply each equation with a suitable multiplier.

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Case (i):

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\"\"          (First equation)

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\"\"      (Divide each side by \"\")

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\"\"                   (Cancel common terms)

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\"\"         (Multiply each side by \"\")

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\"\"                   (Multiply)

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Case (ii):

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\"\"             (Second equation)

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\"\"         (Divide each side by \"\")

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\"\"                   (Cancel common terms)

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Step 2:

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Add the equations to eliminate the one variable.

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\"\"

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\"\"                    (Divide each side by \"\")

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\"\"                                (Cancel common terms)

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Step 3:

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Substitute \"\" into any original equation to find \"\" value. 

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\"\"                   (Second equation)

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\"\"                 (Substitute \"\")

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\"\"                   (Multiply)

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\"\"   (Subtract \"\" from each side)

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\"\"                        (Apply additive inverse property: \"\")

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\"\"                   (Divide each side by \"\")

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\"\"                            (Cancel common terms)

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The solution of the system is \"\".

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\"\"

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The solution of the system is \"\".