From the diagram, for the opposite side is p and hypotenuse is q.
(Definition of sine ratio)
(Substitute: opposite side = p and hypotenuse = q)
The ratio is .
The solution is C.
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the opposite side is p and hypotenuse is q. ![\"\"](\"http://www.mathskey.com/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=46e5269f3473af788dac83636b47be89.png\")
(Definition of sine ratio) ![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=368c02a754f042a1bf9d85aae315a172.png\")
(Substitute: opposite side = p and hypotenuse = q) ![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=64670953d84427b199e612688f40d010.png\")
.![\"\"](\"http://www.mathskey.com/userfiles/image/steps_images/solution.JPG\")