The function is
.
The first term of zero will not shift the graph of
vertically.
The factor of 2 will double the y - coordinates.To determine the horizontal shift and period, We check one cycle.
\One cycle : 


.
A cycle will begin at
, so the graph is
units to the left.
To find the period, we compute the difference between end points for the cycle :
\Period 
.
Dividing the period by 4 gives us
, so we mark the x - axis at intervals of
.
Beginning with
as follows(we only need to find the three middle points).

A cycle will begin and end with x - intercepts at
and
(on the shifted axis).
There will be a vertical asymptote at
.
\