The function is .
The first term of zero will not shift the graph of vertically.
The factor of 2 will double the y - coordinates.To determine the horizontal shift and period, We check one cycle.
\One cycle :
.
A cycle will begin at , so the graph is
units to the left.
To find the period, we compute the difference between end points for the cycle :
\Period
.
Dividing the period by 4 gives us , so we mark the x - axis at intervals of
.
Beginning with as follows(we only need to find the three middle points).
A cycle will begin and end with x - intercepts at and
(on the shifted axis).
There will be a vertical asymptote at .
\