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1.3.2)

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Given data :

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Fired angle θ = 20°

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Initial velocity v₀ =  250 m/s

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Earth gravity g = 9.8 m/s

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The maximum height reached by the bullet H_max = ?

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Formula :

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Maximum height H_max = (v₀²sin²θ)/2g

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Substitute : v₀ =  250 m/s , θ = 20° and  g = 9.8 m/s.

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H_max = (250²sin²20) / (2×9.8)

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H_max = (62500×0.0119) / (19.6)

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H_max = 373.02 m

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Maximum Height  H_max = 373.02 m.

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