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1.3.3)

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Given data :

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Fired angle θ = 20°

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Initial velocity v₀ =  250 m/s

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Earth gravity g = 9.8 m/s

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The horizontal displacement reached by the bullet d = ?

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Formula :

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Horizontal displacementd = (v₀²sin2θ)/g

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Substitute : v₀ =  250 m/s , θ = 20° and  g = 9.8 m/s.

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d = (250²sin(2×20)) / (9.8)

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d = (250²(0.64)) / (9.8)

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d = 4099.41 m

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The horizontal displacement is 4099.41 meters

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