Step 1:

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The molality of sucrose solution is m = 1 molal.

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The molality of glucose solution is m = 1 molal.

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The sucrose and glucose solutions are decomposed in water.

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\"\" for \"\" is 1.86 \"image\".

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Freezing point is \"\".

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Where,

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\"\" is the change in temperature.

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\"\" is the molality depression constant.

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m is the molality .

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i  is the von t Hoff factor.

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Step 2:

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Sucrose :

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C12H22O11 --------> 12C + 11H2O

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Here i = 12 for sucrose, ( sucrose completely dissociates into 12 ion).

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\"\"

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\"\"

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Freezing point of sucrose solution is \"\".

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Freezing point of sucrose \"\".

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Glucose :

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C6H12O6 --> 6C + 6H2O

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Here i = 6 for sucrose, ( sucrose completely dissociates into six ion).

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\"\"

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\"\"

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Freezing point of sucrose solution is \"\".

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Freezing point of sucrose \"\".

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So 1 molal aqueous solution of sucrose show more (Twice) freezing point depression than a 1 molal aqueous solution of glucose.

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