(10)
\Step 1:
\Perimeter of the three pens is ft
Let each pen has length ft and breadth
ft.
Since there are three pens total length is .
Total width is .
ft.
. \ \
Area of the total fencing is .
Substitute .
.
The area of the rectangular field is always positive.
\ and
.
and
.
is positive on the interval
.
Step 2:
\Find the dimensions of the rectangular field, that will enclose the maximum area.
\Apply derivative on each side with respect to .
Find the critical numbers by equating .
ft.
Substitute in
.
ft.
Step 3:
\The maximum value of occurs at either at critical number or at end point of the interval
.
Substitute in
.
.
Substitute in
.
.
Substitute in
.
sq ft. \ \
The maximum area of a rectangular fencing is sq ft. \ \
The dimensions of the rectangular field are ft and
ft. \ \
Solution:
\The dimensions of the rectangular field are ft and
ft.
The maximum area of a rectangular fencing is sq ft.