(10)

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Step 1:

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Perimeter of the three pens is \"\" ft

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Let each pen has length \"\" ft and breadth \"\" ft.

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Since there are three pens total length is \"\".

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Total width is \"\".

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\"\" ft.

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\"\"

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\"\"

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\"\". \ \

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Area of the total fencing is \"\".

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Substitute \"\".

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\"\"

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\"\"

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\"\".

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The area of the rectangular field is always positive.

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\"\"

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\"\"

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\"image\" and \"\".

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\"image\" and \"image\".

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\"\" is  positive on the interval \"image\".

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Step 2:

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Find the dimensions of the rectangular field, that will enclose the maximum area.

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\"\"

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Apply derivative on each side with respect to \"image\".

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\"\"

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\"\"

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\"\"

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Find the critical numbers by equating \"image\".

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\"\"

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\"\"

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\"image\" ft.

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Substitute \"image\" in \"\".

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\"\"

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\"\"

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\"\" ft.

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Step 3:

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The maximum value of \"image\" occurs at either at critical number or at end point of the interval \"\".

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Substitute \"image\" in \"\".

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\"\".

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Substitute \"\" in \"\".

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\"\"

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\"\"

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\"\"

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\"\".

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Substitute \"\" in \"\".

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\"\"

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\"\"

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\"\"

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\"\"

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\"\" sq ft. \ \

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The maximum area of a rectangular fencing is \"\" sq ft. \ \

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The dimensions of the rectangular field are \"\" ft and \"\" ft. \ \

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Solution:

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The dimensions of the rectangular field are \"\" ft and \"\" ft.

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The maximum area of a rectangular fencing is \"\" sq ft.