![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=59332405e64b4ba6d426a9115d9070c2.png\")
.Step 1:
\The coefficient of static friction is 0.40.
\The coefficient of kinetic friction is 0.35.
\Horizontal force is 100 N.
\Mass of the box is 20.0 kg.
\Force due to kinetic friction .
Normal Force ![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=8b01467ab8ec0c7f5bdfbfa415f2d7c0.png\")
, then ![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=a594ad4eb1a6c86bd4dccd85533486c5.png\")
![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=94de1e6bd8fa6a68cd72502db61d8fb8.png\")
.
![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=25c18a9fce08636d9ab871b5cffa5e3e.png\")
Net force ![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=099341b847c755b8ea5a857ecbc31db6.png\")
![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=cd22ec8761811f7c59dbc8e625af8027.png\")
![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=487b970253c8ab1f2f79e0d808597001.png\")
Net force of the block is 100 N.
\As the applied horizontal force is less than the maximum value (Frictional force), the applied is cancelled out by an equal and opposite force and the block remains at rest.
\Solution:
\Net force of the block is 100 N.
\The block remains a rest.