\"\"

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The number is \"\" .

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Consider \"\".

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\"\".

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Newtons approximation formula : \"\".

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Consider \"\".

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Apply derivative on each side with respect to \"\".

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\"\"

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\"\".

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From the newtons method,  \"\".

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We have \"\"  and \"\" is close to the \"\".

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So consider \"\".

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Substitutte \"\" in \"\".

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\"\"

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Substitutte \"\" in above expression.

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\"\"

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Repeat the process to get the value of the root, correct to eight decimal places are same.

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\"\"

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Consider \"\".

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Substitutte \"\" in above expression.

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\"\".

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Substitutte \"\" in above expression.

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\"\"

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\"\"

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\"\"

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\"\"

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Hence \"\"

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Approximation of the number \"\" is  \"\".

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\"\"

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Approximation of the number \"\" is  \"\".