The inequality is .
Factor the related equation .
.
Now, there are two ways this product could be less than zero. One factor must be negative and one must be positive.
\Case 1:
There are NO values for which this situation is true.
\ Case 2:
Note that the original inequality contains a symbol. This means that the solution set contain the endpoints of the intervals.
Solution set of the inequality is .
The solution set in the interval notation is .
Observe the graph the closed circle means and
are include in the solution set.
Set notation: .
Interval notation: .