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| PAGE: 392 | SET: Exercises | PROBLEM: 96 |

(a)
An object is dropped from the height of
.
Let the velocity of a object at time
be
.
Velocity at time
is
.
Initial velocity is zero.
Acceleration is equal to acceleration of gravity
.


Graph :
Graph the initial velocity
:
.gif)
Velocity of the object at time
is
.
(b)
Velocity of the object at time
is
.
Velocity of the object is the rate of change in distance
.
Integrate on both sides.


At
, height
then
.

Therefore the position function is
.
(c)
If air resistance is considered then rate of change in velocity is
.


Integrate on both sides.



At
, Velocity
then
.

Velocity function is
.
(d)
Find
.

Substitute
in the function.



Therefore
.
(e)
Velocity function is
.
Integrate the velocity function.






At
, height
then
.
.
Substitute
in the velocity function.

.
Graph :
Graph the function
and
.
(1).gif)
Time required for the object to reach the ground.

Time required when air resistance was neglected is
.
Therefore additional time taken by air resistance is

Additional time required to reach ground when air resistance is considered is
.
(f)
If
value is increased then the time taken by the object to reach ground decreases.
Consider
.

Time taken by the object to reach ground when air resistance is not considered is
.
Time taken by the object to reach ground when air resistance is considered is
.
The time taken by the object to reach ground decreases when air resistance is considered.
(a) Velocity of the object at time
is
.
(b) The position function is
.
(c) Velocity function when air resistance is considered is
.
(d)
.
(e) Additional time taken to reach ground
.
(f) The time taken by the object to reach ground decreases when
is increased.

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