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Step-by-step Answer
PAGE: 221SET: ExercisesPROBLEM: 9
Please look in your text book for this problem Statement

(a)

The function is .

Differentiate on each side with respect to .

Find the critical points.

Since it is a polynomial it is continuous at all the point.

Thus, the critical points exist when .

Equate to zero.

and

and .

The critical points are and .

The test intervals are .

Interval Test Value Sign of Conclusion
Increasing
Decreasing
Increasing

Therefore the function is increasing on the intervals and .

The function is decreasing on the interval .

(b)

Find the local maximum and local minimum.

The function has a local maximum at , because changes its sign from positive to negative.

Substitute in .

Local maximum is .

The function has a local maximum at , because changes its sign from positive to negative.

Local minimum is .

(c)

.

Differentiate on each side with respect to .

Find the inflection points.

Equate to zero.

The inflection point is at .

Substitute in .

The test intervals are and .

Interval

Test Value Sign of Concavity
Down

Up

The graph is concave up on the interval .

The graph is concave down on the interval .

The inflection point is .

(a)

Increasing on the intervals and .

Decreasing on the interval .

(b)

Local maximum is  .

Local minimum is

(c)

Concave up on the interval .

Concave down on the interval .

Inflection point is .



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