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determine the sum for the geometric sequence:

0 votes
n=12 , r=3 , T1 = 1/9.
asked Mar 18, 2014 in ALGEBRA 2 by harvy0496 Apprentice

1 Answer

0 votes

Given geometric sereis T1 = 1/9 = a

r = 3

Formula for Sum in geometric sereis = a (r^n  - 1) / (r - 1) where r > 1.

Sum = 1/9 (3^12 - 1) / (3-1)

= 1/9 (531441 - 1) / 2

= 531440/18

Sum = 29524.44.

answered Mar 18, 2014 by david Expert

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