Welcome :: Homework Help and Answers :: Mathskey.com

Recent Visits

  
Welcome to Mathskey.com Question & Answers Community. Ask any math/science homework question and receive answers from other members of the community.

13,435 questions

17,804 answers

1,438 comments

774,937 users

Determine, E, 0.1% proof stress, tensile strength, % elongation after failure

0 votes

Maximum force was 13.8kN and final length between gauge warks was 53.35mm

 

Load (N)                      2,000        4,000     6,000    8,000      10,000     11,000    12,000      13,000
 
Extension (mm)         0.060         0.110    0.175    0.225       0.285       0.325       0.475        0.58
 
asked Aug 3, 2014 in PHYSICS by Adam lallana Rookie

1 Answer

+1 vote
 
Best answer

Calculate the E.

First draw the stress-strain curve:

From the graph:

Modulus of elasticity, E = stress/strain

                                    =10000/0.285

                                    =35087.72 N/mm^2

                                     =35087.72 MPa

0.1% proof stress means 0.1% of E.

σ proof  = (0.1/100) *35087.72

          =35.08 MPa

Calculate the tensile strength.

σy= stress/strain

    =11000/0.325

   =33846.154 N/mm^2

   =33846.143 MPa

Strain at failure is 0.58 mm

Initial gage length ,0.06 mm

% of elongation =( 0.58-0.06)*100/(0.06)

                         =52%

 

answered Aug 4, 2014 by bradely Mentor
selected Aug 4, 2014 by Adam lallana
Thank you so much, perfectly clear on what you've said and it helped me a lot.

Related questions

asked Oct 27, 2014 in PHYSICS by anonymous
asked Aug 4, 2014 in PHYSICS by anonymous
asked Aug 4, 2014 in PHYSICS by anonymous
asked Jul 22, 2014 in PHYSICS by anonymous
asked Oct 28, 2014 in PHYSICS by anonymous
asked Oct 28, 2014 in PHYSICS by anonymous
asked Oct 27, 2014 in PHYSICS by anonymous
asked Oct 27, 2014 in PHYSICS by anonymous
asked Oct 27, 2014 in PHYSICS by anonymous
...