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What is the equation of the ellipse with co-vertices (0, 2), (0, -2) and vertices (3, 0), (-3, 0)?

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What is the equation of the ellipse with co-vertices (0, 2), (0, -2) and vertices (3, 0), (-3, 0)?
A. x squared divided by 4 minus y squared divided by 9 equals 1
B. x squared divided by 4 plus y squared divided by 9 equals 1
C. x squared divided by 9 plus y squared divided by 4 equals 1
D. x squared divided by 9 minus y squared divided by 4 equals 1

 

asked Sep 9, 2014 in ALGEBRA 2 by tonymate Pupil

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The vertices lie on the line y=0 which is horizontal. This means the major axis is the x-axis.

The horizontal ellipse equation is x2/a2 + y2/b2 = 1

Vertices : (± a, 0) = (± 3, 0)  ----->   a = 3

Co-vertices : (0, ±b) = (0, ± 2)  ----->   b = 2.

Substitute a = 3 and b = 2 in the ellipse equation.

x2/(3)2 + y2/(2)2 = 1

x2/9 + y2/4 = 1

The option C is correct.

 

answered Sep 9, 2014 by bradely Mentor
edited Sep 9, 2014 by moderator
Please check the updated answer.

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