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HElP PLEASE :(

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A ball that is hit thrown horizontally with a velocity of V metres per second will travela distance metres before hitting the ground, where d=√h/4=g and h is the height, in metres from which the ball was hit or thrown. How far will a ball that is hit with a velocity of 45m/s at a height of 0.8m above the ground travel before hitting the ground to the nearest metres.
 
asked Nov 21, 2014 in PRECALCULUS by anonymous

Please provide us the correct expression of d.

A ball that is hit thrown horizontally with a velocity of V metres per second will travela distance metres before hitting the ground, where d=v√h/4=g and h is the height, in metres from which the ball was hit or thrown. How far will a ball that is hit with a velocity of 45m/s at a height of 0.8m above the ground travel before hitting the ground to the nearest metres. 
 
I forgot to put V in there. they dont give expression for d(distance) :(
 
 

1 Answer

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Distance Travelled by the ball before hitting the ground is d = (v√h)/4g

Where v is the velocity and h is the height of ball above the ground.

The Height above the ground is 0.8

Velocity of the ball is 45 m/sec

Distance travelled d = (v√h)/4g

d = (45*√0.8)/(2*9.8) = 2.0535

Therefore the distance travelled before hitting the ground is 2.0535 mts.

answered Nov 21, 2014 by Lucy Mentor

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