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The probability Dick chooses choccolate ice cream is 0.8.

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The probability Jane chooses vanilla is 0.6. The probability Dick chooses chocolate and jane does not choose vanilla is?

asked Dec 6, 2014 in STATISTICS by anonymous

1 Answer

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The Probabilty of Dick choosing ice cream P(A) is 0.8

The Probabilty of Jane choosing Vanilla P(B) is 0.6

The Probabilty of Jane not choosing Vanilla image = 1 - P(B) ⇒ 1 - 0.6 ⇒ 0.4

The two events(Dick choosing ice cream and Jane not choosing Vanilla) are independent events then image

The Probabilty of Dick choosing ice cream and Jane not choosing Vanilla is

image

Therefore the Probabilty of Dick choosing ice cream and Jane not choosing Vanilla is 0.32.

answered Dec 6, 2014 by Lucy Mentor

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