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Let f(x)= { [4x+1-sin(pi/x), x<2] [cube root 3sqrt(3^x -1), x ≥ 2] }

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Let f(x)= { [4x+1-sin(pi/x), x<2]  [cube root 3sqrt(3^x -1), x ≥ 2] }

a) Find lim x approaching 2 from the left f(x) and lim x approacvhes 2 from the right f(x).

b) Find lim x approaching 2 f(x) or explain why it does not exist
asked Jan 21, 2015 in CALCULUS by anonymous

1 Answer

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Step 1:

a) The piece wise function image

 

Find limit of image ,as image approaches 2 from the left side.

image

image

image

image.

Step 2:

Find limit of image, as image approaches 2 from the right side.

image

image.

Step 3:

b) image and image.

Since the left hand side limit is not equal to the right hand side limit, limit doesn't exists.

The limit of image doesn't exists as image approaches to 2.

Solution:

a) image and image.

b) The limit of image doesn't exists as image approaches to 2.

answered Jan 21, 2015 by cameron Mentor

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