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Find the center,transverse axis,vertices,foci,and asymptotes.Graph the equation.

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Find the center,transverse axis,vertices,foci,and asymptotes.Graph the equation.

4x^2 - y^2 = 16
asked Feb 3, 2015 in PRECALCULUS by anonymous

1 Answer

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Step 1:

The equation is .

Divide each side by 16.

Compare the above equation with .

So the equation is in the standard form of the hyperbola.

The center of the hyperbola is .

Step 2:

The hyperbola has a transverse axis parallel to axis.

The foci of the hyperbola is .

The vertices of the hyperbola is .

Find the points to form a rectangle.

.

image.

The extensions of the diagonals of the rectangle are the asymptotes of the hyperbola.

Asymptotes of the hyperbola are .

Substitute the values of in .

Asymptotes are .

Step 3:

Graph :

(1) Draw the coordinate plane.

(2) Draw the equation of the hyperbola.

(3) Plot the foci and vertices.

(4) Form a rectangle containing the points image and image.

(5) Draw the asymptotes of the hyperbola.

image
 

Solution :

The center of the hyperbola is image.

The hyperbola has a transverse axis parallel to axis.

The vertices of the hyperbola is image.

The foci of the hyperbola is image.

Asymptotes of the hyperbola are .

answered Feb 6, 2015 by joseph Apprentice

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