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help? plz? (critical points -extrema]

0 votes

asked May 3, 2015 in CALCULUS by anonymous

2 Answers

0 votes

(11)

Step 1:

The function is and interval is .

Absolute maxima or minima are exist either at the end points or at the critical numbers.

Find the critical numbers :

is differentiable at all points because its a polynomial.

Therefore the solutions of image are the only critical numbers.

Differentiate on each side with respect to t.

Equate to zero.

and and

and and

The critical number are , and .

The end points are and .

answered May 4, 2015 by joseph Apprentice

Contd....

Step 2:

Find the value of f  at the critical numbers.

Substitute in .

.

Substitute in .

.

Substitute in .

.

Step 3:

Find the value of f  at the end points of the interval.

Substitute in .

.

Substitute in .

.

Since the largest value is , absolute maximum is .

Since the smallest value is , absolute minimum is .

Solution :

Absolute maximum is .

Absolute minimum is .

0 votes

(12)

Step 1:

The function is and interval is image.

Absolute maxima or minima are exist either at the end points or at the critical numbers.

Find the critical numbers :

image is differentiable at all points because its a polynomial.

Therefore the solutions of image are the only critical numbers.

Differentiate image on each side with respect to x.

image

Equate image to zero.

image

The critical number are image.

The end points are image and image.

Step 2:

Find the value of h  at the critical numbers.

Substitute image in image.

image

image.

answered May 4, 2015 by joseph Apprentice

Contd.....

Find the value of h  at the end points of the interval.

Substitute image in image.

image

image.

Substitute image in image.

image

image.

Since the largest value is image, absolute maximum is image.

Since the smallest value is image, absolute minimum is image.

Solution :

Absolute maximum is image.

Absolute minimum is image.

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