Welcome :: Homework Help and Answers :: Mathskey.com

Recent Visits

    
Welcome to Mathskey.com Question & Answers Community. Ask any math/science homework question and receive answers from other members of the community.

13,435 questions

17,804 answers

1,438 comments

777,429 users

help-area-curves?

0 votes

asked May 15, 2015 in CALCULUS by anonymous

2 Answers

0 votes

5)

Step 1:

The curve equations is image and the image-axis is equation is image.

And the vertical boundaries are image and image.

The area of a region bounded by a graph of a function, the image-axis, and two vertical boundaries can be determined directly by evaluating a definite integral.

If image on image, then the area image of the region lying below the graph of image, above the image-axis, and between the lines image and image  is image.

Step 2:

Graph the region:

Since image on image, then the area image of the region lying below the graph of image, above the image-axis, and between the lines image and image  is image.

Apply the power rule in integration:image.

answered May 15, 2015 by david Expert

Contd..

image

image

image

image

image

image

image

image square units.

Solution:

image square units.

0 votes

6)

Step 1:

The curve equation is image and the image-axis equation is image.

Formula for the area is image.

In this case image.

Find the limits of integration.

image

image

image and image

image and image.

Step 2:

The curve image is intersect the image-axis at image.

The area of the region is image.

image

image

image

image

image

image

image square units.

Solution:

image square units.

answered May 15, 2015 by david Expert

Related questions

asked May 15, 2015 in CALCULUS by anonymous
asked May 15, 2015 in CALCULUS by anonymous
asked Feb 11, 2015 in CALCULUS by anonymous
asked Jul 10, 2015 in CALCULUS by anonymous
asked Jun 2, 2015 in CALCULUS by anonymous
asked Jun 2, 2015 in CALCULUS by anonymous
asked Jun 2, 2015 in CALCULUS by anonymous
asked Jun 2, 2015 in CALCULUS by anonymous
asked May 15, 2015 in CALCULUS by anonymous
asked May 15, 2015 in CALCULUS by anonymous
asked May 15, 2015 in CALCULUS by anonymous
...