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Use the Limit Laws to find the limit

0 votes

limit as (x to 5) [x^3-125]/[x-5]

asked Dec 9, 2017 in CALCULUS by anonymous

1 Answer

0 votes

limit as (x to 5) [x^3-125]/[x-5]

=limit as (x to 5) [x-5][x^2+5x+5^2]/[x-5]

=limit as (x to 5) [x^2+5x+5^2]

=5^2+5*5+5^2

=25+25+25

=75

 

answered Dec 9, 2017 by johnkelly Apprentice

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