Welcome :: Homework Help and Answers :: Mathskey.com

Recent Visits

    
Welcome to Mathskey.com Question & Answers Community. Ask any math/science homework question and receive answers from other members of the community.

13,435 questions

17,804 answers

1,438 comments

776,666 users

Dividing Rational Expressions

0 votes

equation

asked Jan 2, 2018 in ALGEBRA 1 by anonymous

1 Answer

0 votes

[(3a^2 - 3a - 36)/(2a^2 + 8a - 10)] / [(a^2 - a - 12)/(a^2 + 3a - 10)]

                =   [3(a^2 - a - 12)/2(a^2 + 4a - 5)] X [(a^2 + 3a - 10)/(a^2 - a - 12)]

                        =   3(a^2 + 3a - 10) / 2(a^2 + 4a - 5)

                        =   3(a^2 + 5a - 2a - 10) / 2(a^2 + 5a - a - 5)

                        =   3[ a(a + 5) - 2(a + 5) ] / 2[a(a + 5) - 1(a + 5)]

                        =   3[ (a + 5)(a - 2) ] / 2[a(a + 5) - 1(a + 5)]

                        =   3[ (a + 5)(a - 2) ] / 2[(a + 5)(a - 1)]

                        =   3(a - 2) / 2(a - 1)

Hence,

[(3a^2 - 3a - 36)/(2a^2 + 8a - 10)] / [(a^2 - a - 12)/(a^2 + 3a - 10)]   =   3(a - 2) / 2(a - 1)

 

answered Sep 28, 2018 by homeworkhelp Mentor
edited Sep 29, 2018 by bradely

Related questions

asked Oct 24, 2014 in ALGEBRA 2 by anonymous
asked Dec 11, 2014 in ALGEBRA 1 by anonymous
...