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1) mv^2/R=GMm/R^2 solve for v 2) T =2pisqrt(L/g) solve for g 3) A = 2πτ^2 + 2πrh solve for h
asked Sep 9, 2018 in ALGEBRA 2 by abstain12 Apprentice
reshown Sep 9, 2018 by bradely

1 Answer

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1)

m v^2 / R  =  GMm / R^2

m v^2  =  (GMm / R^2 ) X R

m v^2  =  (GMm / R )

v^2  =  (GMm / R ) / m

v^2  =  (GMm / Rm )

v^2  =  (GM / R )

Apply square root on each side

v  =   √ (GM / R )

2)

T  =  2(pi) √(L/g)

T / 2(pi)  √(L/g)

Apply square root on each side

[ T / 2(pi) ]^2  =  L/g

g[ T / 2(pi) ]^2  =  L

g  =  L / [ T / 2(pi) ]^2

3)

A  =  2πτ^2 + 2πrh

A - 2πτ^2  =  2πrh

[ A - 2πτ^2 ] / (2πr)   =  h

h  =  [ A - 2πτ^2 ] / (2πr)

Answer :

1)  v  =   √ (GM / R )

2)  g  =  L / [ T / 2(pi) ]^2

3) h  =  [ A - 2πτ^2 ] / (2πr)

answered Sep 28, 2018 by homeworkhelp Mentor
reshown Sep 29, 2018 by bradely

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