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Find all positive values of x:

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7^(x^2 + x) = 49?

asked Oct 7, 2018 in ALGEBRA 2 by anonymous

1 Answer

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7^(x^2+x)= 49

49=  7*7 =7^2

x^2+x = 2

x^2+x-2=0

x^2+2x-x-2=0

x(x+2)-1(x+2)=0

(x-1) (x+2)=0

x = 1; x= -2.

The positive value of x is 1.
answered Oct 8, 2018 by tarun mahanti Rookie

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