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Simplify

0 votes

Simplify

asked Oct 28, 2018 in ALGEBRA 1 by anonymous
reshown Oct 28, 2018 by bradely

1 Answer

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17)

2mn^2(5mn^2)^(1/3)  =  2mn^2(5mn^2)^(1/3)

                                   =  2mn^2[ 5^(1/3)m^(1/3)n^(2/3) ]

                                   =  2[5^(1/3)]m^(1 + 1/3)n^(2 + 2/3) ]

                                   =  2[5^(1/3)]m^(3+1)/3 ] [n^(6 + 2)/3 ]

                                   =  2[5^(1/3)]m^4/3 ] [n^8/3 ]

Answer :

2mn^2(5mn^2)^(1/3)  =  2[5^(1/3)]m^4/3 ] [n^8/3 ].

answered Nov 3, 2018 by homeworkhelp Mentor

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