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solve inequalities!!!!!!!!!!!!!!!!!!!

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Solve 5x + 7 < 2 and 5x + 7 > - 18

asked Jul 15, 2013 in ALGEBRA 1 by anonymous Apprentice

2 Answers

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5x + 7 < 2

Subtract 7 from each side

5x + 7 - 7 < 2 - 7

5x + 0 < -5

5x < -5

Divide each side by 5

x < -1.

answered Jul 15, 2013 by diane Scholar

Solution of the inequality 5x + 7 < 2 is {x | x < - 1}.

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5x + 7 > -18

Subtract 7 from each side

5x + 7 - 7 > -18 - 7

5x + 0 > -25

5x > -25

Divide each side by 5

x > -5.

 

answered Jul 15, 2013 by diane Scholar

Solution of the inequality 5x + 7 > - 18 is {x | x > - 5}.

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