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what is the perimeter of the triangle with vertices (-1,6) (7,0) and (0,-1)

0 votes

college algebra do not understand it

asked Dec 3, 2013 in GEOMETRY by abstain12 Apprentice

1 Answer

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Let the triangle vertices  A(-1,6) B(7,0)C(0,-1)

Assume ABC is a triangle.

Now find the lengths of triangle.

AB = [(7+1)^2+(0-6)^2]

= (64+36)

= 10

BC = [(0-7)^2+(-1-0)^2]

= (49+1)

= √50

CA = [(-1-0)^2+(6+1)^2]

= (1+49)

= √50

Perimeter = AB+BC+CA

= 10+√50+√50

= 10+2√50

answered Dec 3, 2013 by william Mentor

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