Welcome :: Homework Help and Answers :: Mathskey.com
Welcome to Mathskey.com Question & Answers Community. Ask any math/science homework question and receive answers from other members of the community.

13,435 questions

17,804 answers

1,438 comments

774,935 users

draw the graph of linear equation 5x-2y-10=0

0 votes
from the graph ,find the value of abscissa when the value of ordinate is 5

 

asked Dec 5, 2013 in ALGEBRA 1 by angel12 Scholar

1 Answer

0 votes

The equation is 5x - 2y - 10 = 0

Write the equation in slope-intercept form y = mx + b, where m is slope and b is y-intercept.

5x - 2y - 10 = 0

y =  5x/2 - 5

Compare the equation with slope-intercept form y = mx + b.

slope = 5/2 and y - intercept is - 5.

y-intercept is - 5, so the line crosses the y - axis at (0, - 5)

Using slope find the next point.

Slope = rise/run = 5/2

Start at point (0, - 5), move 5 units up and 2 units right, then plot the point (0, 2).

Draw a line through these points.

Graph :

graph for the equation - x - 2y = 8

From the graph the value of abscissa is 4 when the value of ordinate is 5.

answered Aug 25, 2014 by david Expert

Related questions

asked Nov 17, 2014 in ALGEBRA 2 by anonymous
...