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derivative f(x) = sin x + (3/2x^2)

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derivative f(x) = sin x + (3/2x^2).

asked Feb 21, 2014 in CALCULUS by abstain12 Apprentice

1 Answer

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Remember the formulae d/dx(Sinx) = Cosx

d/dx(x^n) = nx^(n-1)

f(x) = Sinx+(3/2x^2)

Apply derivative on each side with respect of x.

f'(x) = d/dx[Sinx+(3/2x^2)]

= d/dx(Sinx)+(3/2)d/dx(x^-2)

f'(x) = Cosx-3/x^3

answered Feb 21, 2014 by friend Mentor

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