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How do I find the local and extreme values of a function on a given interval.

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Find the local and absolute extreme values of the function on the given interval.  f(x)=3x/2x^2+5,  [0,3]

asked Feb 26, 2014 in CALCULUS by linda Scholar

1 Answer

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Given function f(x) = 3x/2x^2+5

Given interval a = 0, b = 3.

f(0) = 3(0)/2(0)^2+5 = 0

f(3) = 3(3)/(2(3)^2+5) = 9/21

f'(x) = f(b)-f(a)/b-a

= [(9/21)-0]/(3-0)

= 1/7.

answered Feb 26, 2014 by friend Mentor

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