![\"\"](\"http://www.mathskey.com/userfiles/image/steps_images/step1.JPG\")
Graph by Making a Table:
\The equation is ![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=e646716c70344f1fbec0b55e8c1aba25.png\")
.
Make a table; choose some values for x and find the corresponding values for y.
\\
| \
x \ | \
\
y = x + 5 \ | \
\
y \ | \
\
(x, y) \ | \
| \
– 2 \ | \
\
= – 2 + 5 = 3 \ | \
\
3 \ | \
\
(– 2, 3) \ | \
| \
– 1 \ | \
\
= – 1 + 5 = 4 \ | \
\
4 \ | \
\
(– 1, 4) \ | \
| \
0 \ | \
\
= 0 + 5 = 5 \ | \
\
5 \ | \
\
(0, 5) \ | \
| \
1 \ | \
\
= 1 + 5 = 6 \ | \
\
6 \ | \
\
(1, 6) \ | \
| \
2 \ | \
\
= 1 + 5 = 7 \ | \
\
7 \ | \
\
(2, 7) \ | \
![\"\"](\"http://www.mathskey.com/userfiles/image/steps_images/step2.JPG\")
Use these ordered pairs to graph the equation.
\1. Draw a coordinate plane.
\2. Plot the points.
\3. Draw a line through these points.
\4.Draw a line ![\"\"](\"http://www.mathskey.com/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=e5877a961396b9907d4693a156a5635b.png\")
.
![\"Compare](\"/userfiles/image/Library/Algebra%202/graph%20of_linear_equations_y=x+5_y=x(1).gif\")
The graph of ![\"\"](\"http://www.mathskey.com/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=e646716c70344f1fbec0b55e8c1aba25.png\")
and both have a slope of 1, but the graph of
has a y-intercept of 5 instead of 0.
\![\"\"](\"http://www.mathskey.com/userfiles/image/steps_images/solution.JPG\")
The graph of and both have a slope of 1, but the graph of
has a y-intercept of 5 instead of 0.