The matrix equation form is
.
When,
.
Therefore solution matrix is
.
First find the determinant of A = ad
bc.



.
Therefore A-1 exists.
The inverse of A is
.
Substitute a = 3, b = 6, c = 2, d =
and ad
bc =
.
.
Substitute the values of
in the solution matrix
Multiply each side by
.






The solution is
.