![\"\"](\"http://www.mathskey.com/userfiles/image/steps_images/step1.JPG\")
From the table, the years are the domain and the prices are the range.
\The relation of ordered pairs for the data is ![\"\"](\"http://www.mathskey.com/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=bab17aabfc5176b2ff1c1e5a94426504.png\")
.
The domain is ![\"\"](\"http://www.mathskey.com/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=5cf1047b2bb69a6856442019c976ca32.png\")
and the range is ![\"\"](\"http://www.mathskey.com/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=15d46d7a4fb967202be54bf24989cfb8.png\")
.
Each member of the domain is paired with exactly one member of the range, so the relation is a function.![\"\"](\"/userfiles/image/steps_images/step2.JPG\")
Draw a coordinate plane.
\Plot the points on the coordinate plane.
\![\"graph](\"/userfiles/image/Library/Algebra%202/graph_the_points_(2002,39),(2003,43),(2004,48),(2005,55),(2006,61),(2007,52).gif\")
Observe the graph, there is no vertical line can be drawn that contains more than one of the data points. Therefore, this relation is a function.![\"\"](\"http://www.mathskey.com/userfiles/image/steps_images/solution.JPG\")
Yes, the relation is a function.