![\"\"](\"http://www.mathskey.com/userfiles/image/steps_images/step1.JPG\")
From the table, the years are the domain and the representatives are the range.
\The relation of ordered pairs for the data is ![\"\"](\"http://www.mathskey.com/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=dcbf3cfea300c048099d302648864a55.png\")
.
The domain is ![\"\"](\"http://www.mathskey.com/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=51e6c3c44a88970cb2ec28520f5e4afc.png\")
and the range is ![\"\"](\"http://www.mathskey.com/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=84d691b3471f1c5477d3d61caaaf669e.png\")
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Each member of the domain is paired with exactly one member of the range, so the relation is a function.![\"\"](\"http://www.mathskey.com/userfiles/image/steps_images/step2.JPG\")
Draw a coordinate plane.
\Plot the points on the coordinate plane.
\![\"graph](\"/userfiles/image/Library/Algebra%202/graph_the_points_(1991,11),(93,12),(95,9),(97,6),(99,3),(01,7),(03,9).gif\")
Observe the graph, there is no vertical line can be drawn that contains more than one of the data points. Therefore, this relation is a function.![\"\"](\"http://www.mathskey.com/userfiles/image/steps_images/solution.JPG\")
Yes, the relation is a function.