
The given line is
.
Above line is slope - intercept form
.
So, given line has a slope of(
) = 0.
So, a line perpendicular to it has a slope of
.
Because you know the slope and a point on the line,
\Use point - slope form
to write an equation of the line.
Let
=
and slope(
) =
.
(Substitute 2 for
,
6 for
and
=
)
Rewrite in slope - intercept form
.
(Product of two same signs is positive)
Apply multiplication property of equality:If a = b then a
c = b
c.
(Multiply each side by 0)
(Cancel common terms)
(Apply zero product property:
)
(Apply distributive property:
)
(Apply multiplicative identity property:
)
Apply subtraction property of equality:If a = b then a
c = b
c.
(Subtract 6 from to each side)
(Apply additive inverse property:
)
(Apply additive identity property:
,
)
Check:
\To check the solution substitute
=
in
.

The equation satisfies the condition.
\So,The equation of the line is
.
The equation of the line is
.