$\"\"$

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Two times the least of three consecutive odd integers exceeds three times the greatest by $\"\"$ .

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Find the integers.

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Let $\"\"$ be the least odd integer then $\"\"$ be the next greater odd integer and $\"\"$ the greatest of the three integers.

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Solve the equation.

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$\"\"$ (Original equation)

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$\"\"$ (Distributive property: $\"\"$ )

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$\"\"$ (Simplify)

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$\"\"$ (Subtract $\"\"$ from each side)

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$\"\"$ (Apply additive inverse property : $\"\"$ )

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$\"\"$ (Multiply each side by negative one)

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Since, the first integer $\"\"$ is $\"\"$ .

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Second integer $\"\"$ is $\"\"$ .

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Third integer $\"\"$ is $\"\"$ .

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Therefore, the consecutive odd integers are $\"\"$ , $\"\"$ and $\"\"$ . $\"\"$

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The consecutive odd integers are $\"\"$ , $\"\"$ and $\"\"$ .