The equation is
.
Solve equation.
\
(Original equation)
(Subtract
from each side)
(Apply additive inverse property:
)
(Square on each side)
(Cancel square and root terms)
(Apply difference of squares:
)
(Evaluate power
)
(Subtract
from each side)
(Apply additive inverse property:
)
(Addition:
)
(Add
to each side)
(Apply additive inverse property:
)
(Addition:
)
(Factors of equation)
(Factors of group terms)
(Take out common terms)
and
(Separate solutions)
and
(Simplify)
Therefore, the value of
are
and
.
Check for solution for
-values:
Case(i):
(Original equation)
(Substitute
in the equation)
(Subtraction:
)
(Substitute:
)
Therefore the value of
is
does not satisified the equation.
Case(ii):
(Original equation)
(Substitute
in the equation)
(Subtraction:
)
(Substitute:
)
(Substitute:
)
Therefore, the value of
is
satisified the equation.
The value of
is
.