The equation is
.
Solve equation.
\
(Original equation)
(Square on each side)
(Cancel square and root terms)
(Evaluate power
)
(Subtract
from each side)
(Apply additive inverse property:
)
Therefore, the value of
is
.
Check for solution for
-values:
(Original equation)
(Substitute
in the equation)
(Multiply)
(Subtraction:
)
(Substitute:
)
Therefore the value of
is
does not satisified the equation.
The solution is
.