The equation is
.
Solve equation.
\
(Original equation)
(Square on each side)
(Cancel square and root terms)
(Evaluate power
)
(Multiply)
(Add
to each side)
(Apply additive inverse property:
)
Therefore, the value of
is
.
Check for solution for
-values:
(Original equation)
(Substitute
in the equation)
(Subtraction:
)
(Substitute:
)
Therefore the value of
is
is satisified the equation.
The value of
is
.