$\"\"$

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Tim $\"\"$ s bank contains quarters,dimes and nickels.

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He has three more dimes than quarter and $\"\"$ fewer nickels than quater.

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If he has $\"\"$ coins.

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Write and solve an equation to find how many quarters tim has.

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Find an equation.

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Let $\"\"$ represents number of quarters he has.

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He has three more dimes than quarter is $\"\"$ .

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He has $\"\"$ fewer nickels than quater, so the number of quarters nickel has $\"\"$

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His total coins is $\"\"$ .

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His total coins equal to the sum of the number of quarters, nickels and dimes.

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Sum of the $\"\"$ and $\"\"$ and $\"\"$ equal sixty three.

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The equation is $\"\"$ .

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$\"\"$

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Find how many quarters tim has.

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$\"\"$ (Original equation)

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$\"\"$ (Add common terms)

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$\"\"$ (Add $\"\"$ to each side)

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$\"\"$ (Apply additive inverse property: $\"\"$ )

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$\"\"$ (Divide each side by $\"\"$ )

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$\"\"$ (Cancel common terms)

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Therefore, he has $\"\"$ quarters.

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$\"\"$

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Check.

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$\"\"$ (Original equation)

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$\"\"$ (Substitute $\"\"$ in the equation)

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$\"\"$ (Add inside terms)

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$\"\"$ (Simplify)

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$\"\"$

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The equation is $\"\"$ .

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He has $\"\"$ quarters.