$\"\"$

\

The equation is $\"\"$ .

\

Solve the equation:

\

$\"\"$ (Original equation)

\

$\"\"$ (Factors the GCF)

\

Since $\"\"$ and $\"\"$ are both perfect cubes, so can be factored using difference of cubes formula.

\

$\"\"$ (Sum of two cubes)

\

$\"\"$ or $\"\"$ (Zero product property)

\

$\"\"$ and $\"\"$ (Simplify)

\

$\"\"$

\

Consider $\"\"$ .

\

$\"\"$ (Quadratic roots formula)

\

$\"\"$ (Substitute $\"\"$ and $\"\"$ )

\

$\"\"$ (Multiply)

\

$\"\"$ (Subtract)

\

$\"\"$ (Simplify)

\

$\"\"$ (Simplify)

\

Since the solution of the equation are $\"\"$ and $\"\"$ .

\

$\"\"$

\

The solutions of the equation are $\"\"$ and $\"\"$ .